What is the sum from n=1 to infinity of (n-1)/n ?

The sum from n=1 to infinity of (n-1)/n is diverges

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sum from n=1 to infinity of (n-1)/n

n = 1 \sum \infty \frac{n - 1}{n}

diverges

Solution steps

n = 1 \sum \infty \frac{n - 1}{n}

Apply Series Divergence Test:

diverges

= diverges

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\frac{\partial}{\partial x} (y cos (x y) - y sin (x y))

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x \to 3 lim (x^{2} + 7)

What is the sum from n=1 to infinity of (n-1)/n ?
The sum from n=1 to infinity of (n-1)/n is diverges