What is the integral of 12x^2+6x-4 ?

The integral of 12x^2+6x-4 is 4x^3+3x^2-4x+C

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integral of 12x^2+6x-4

\int 12 x^{2} + 6 x - 4 d x

4 x^{3} + 3 x^{2} - 4 x + C

Solution steps

\int 12 x^{2} + 6 x - 4 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 12 x^{2} d x + \int 6 x d x - \int 4 d x

\int 12 x^{2} d x = 4 x^{3}

\int 6 x d x = 3 x^{2}

\int 4 d x = 4 x

= 4 x^{3} + 3 x^{2} - 4 x

Add a constant to the solution

= 4 x^{3} + 3 x^{2} - 4 x + C

\frac{\partial}{\partial x} (y cos (x y) - y sin (x y))

h \to 0 lim (\frac{( sin ( \frac{π}{6} + h ) - \frac{1}{2} )}{h})

(t + 4)^{\frac{2}{3}} (3 t^{2} - 2)^{3}

x \to 3 lim (x^{2} + 7)

\frac{d}{d x} (lo g_{2} (8^{x - 5}))

What is the integral of 12x^2+6x-4 ?
The integral of 12x^2+6x-4 is 4x^3+3x^2-4x+C