What is the derivative of log_{2}(8^{x-5}) ?

The derivative of log_{2}(8^{x-5}) is 3

What is the first derivative of log_{2}(8^{x-5}) ?

The first derivative of log_{2}(8^{x-5}) is 3

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\frac{d}{d x} (lo g_{2} (8^{x - 5}))

3

Solution steps

\frac{d}{d x} (lo g_{2} (8^{x - 5}))

Simplify

lo g_{2} (8^{x - 5}) : 3 (x - 5)

= \frac{d}{d x} (3 (x - 5))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (x - 5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= 3 (\frac{d x}{d x} - \frac{d}{d x} (5))

\frac{d x}{d x} = 1

\frac{d}{d x} (5) = 0

= 3 (1 - 0)

Simplify

= 3

(- 11, - 4), (- 10, 5)

\int (\frac{1}{1 + x ^{2}}) d x

x \to 0 lim ((1 + \frac{1}{x})^{x})

\frac{\partial}{\partial y} (x^{3} ln (y^{5}))

\frac{1}{( s + 4 ) ^{3}}

What is the derivative of log_{2}(8^{x-5}) ?
The derivative of log_{2}(8^{x-5}) is 3
What is the first derivative of log_{2}(8^{x-5}) ?
The first derivative of log_{2}(8^{x-5}) is 3