What is the sum from n=1 to infinity of 1-(1/2)^n ?

The sum from n=1 to infinity of 1-(1/2)^n is diverges

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sum from n=1 to infinity of 1-(1/2)^n

n = 1 \sum \infty 1 - (\frac{1}{2})^{n}

diverges

Solution steps

n = 1 \sum \infty 1 - (\frac{1}{2})^{n}

Apply Series Divergence Test:

diverges

= diverges

x \to + (- 1) lim (arccos (x))

f (x) = \frac{9}{5 + x ^{2}}, at x = 4

f (x) = x^{2} + 3, at x = 6

\int \frac{cosh ( x )}{x} d x

\frac{4 - 4 s}{4 s ^{2} + 4 s + 17}

What is the sum from n=1 to infinity of 1-(1/2)^n ?
The sum from n=1 to infinity of 1-(1/2)^n is diverges