What is the tangent of y=x^2+4,(-5,29) ?

The tangent of y=x^2+4,(-5,29) is y=-10x-21

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tangent of y=x^2+4,(-5,29)

tangent of

y = x^{2} + 4, (- 5, 29)

y = - 10 x - 21

Solution steps

Find the slope of

y = x^{2} + 4 : \frac{d y}{d x} = 2 x

Compute the slope of

y = x^{2} + 4

(- 5, 29) : m = - 10

Find the line with slope m=

- 10

and passing through

(- 5, 29) : y = - 10 x - 21

y = - 10 x - 21

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What is the tangent of y=x^2+4,(-5,29) ?
The tangent of y=x^2+4,(-5,29) is y=-10x-21