What is the tangent of 1/(x^2)(1.1) ?

The tangent of 1/(x^2)(1.1) is y=-(2.2)/(a_{0)^3}x+(3.3)/(a_{0)^2}

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tangent of 1/(x^2)(1.1)

tangent of

\frac{1}{x ^{2}} (1.1)

y = - \frac{2.2}{a _{0}^{3}} x + \frac{3.3}{a _{0}^{2}}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, \frac{1.1}{a _{0}^{2}})

Find the slope of

y = \frac{1}{x ^{2}} 1.1 : \frac{d y}{d x} = - \frac{2.2}{x ^{3}}

Compute the slope of

y = \frac{1}{x ^{2}} 1.1

x = a_{0} : m = - \frac{2.2}{a _{0}^{3}}

Find the line with slope m=

- \frac{2.2}{a _{0}^{3}}

and passing through

(a_{0}, \frac{1.1}{a _{0}^{2}}) : y = - \frac{2.2}{a _{0}^{3}} x + \frac{3.3}{a _{0}^{2}}

y = - \frac{2.2}{a _{0}^{3}} x + \frac{3.3}{a _{0}^{2}}

\int + 4 x (x^{2} - 3)^{5} d x

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\frac{\partial}{\partial x} (x^{x^{2} - y^{2}})

\frac{d}{d x} (\frac{( - 2 x ^{2} + 2 x )}{( 3 x - 3 )})

\frac{d}{d x} (\frac{40}{3 x ^{\frac{1}{3}}})

What is the tangent of 1/(x^2)(1.1) ?
The tangent of 1/(x^2)(1.1) is y=-(2.2)/(a_{0)^3}x+(3.3)/(a_{0)^2}