What is (\partial)/(\partial x)(x^5-6x+4y^3-y^2) ?

The answer to (\partial)/(\partial x)(x^5-6x+4y^3-y^2) is 5x^4-6

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(\partial)/(\partial x)(x^5-6x+4y^3-y^2)

\frac{\partial}{\partial x} (x^{5} - 6 x + 4 y^{3} - y^{2})

5 x^{4} - 6

Solution steps

\frac{\partial}{\partial x} (x^{5} - 6 x + 4 y^{3} - y^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{5}) - \frac{\partial}{\partial x} (6 x) + \frac{\partial}{\partial x} (4 y^{3}) - \frac{\partial}{\partial x} (y^{2})

\frac{\partial}{\partial x} (x^{5}) = 5 x^{4}

\frac{\partial}{\partial x} (6 x) = 6

\frac{\partial}{\partial x} (4 y^{3}) = 0

\frac{\partial}{\partial x} (y^{2}) = 0

= 5 x^{4} - 6 + 0 - 0

Simplify

= 5 x^{4} - 6

(4.6) (3.1)

f (9) = 3.6 x + 500

\frac{\partial}{\partial x} (ln (y) \cdot ln (x^{2} + 1))

\int x (5 x + 1)^{19} d x

\int e^{- b t} d t

What is (\partial)/(\partial x)(x^5-6x+4y^3-y^2) ?
The answer to (\partial)/(\partial x)(x^5-6x+4y^3-y^2) is 5x^4-6