What is (\partial)/(\partial x)(6x^3y^2) ?

The answer to (\partial)/(\partial x)(6x^3y^2) is 18x^2y^2

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(\partial)/(\partial x)(6x^3y^2)

\frac{\partial}{\partial x} (6 x^{3} y^{2})

18 x^{2} y^{2}

Solution steps

\frac{\partial}{\partial x} (6 x^{3} y^{2})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 6 y^{2} \frac{\partial}{\partial x} (x^{3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 6 y^{2} \cdot 3 x^{3 - 1}

Simplify

= 18 x^{2} y^{2}

x \to 1 lim ((5 x - 1)^{- 2})

\frac{d}{d x} ((4 x - 4) (3 x^{3} - x^{2} + 1))

y = \frac{1}{16 x ^{2}}, y = x, y = \frac{x}{18}

f (x) = sin (cos (4 x))

\int 4 x cos (4 x) d x

What is (\partial)/(\partial x)(6x^3y^2) ?
The answer to (\partial)/(\partial x)(6x^3y^2) is 18x^2y^2