What is the derivative of f(x)= 3/8 x^4-2-(10)/x ?

The derivative of f(x)= 3/8 x^4-2-(10)/x is (3x^3)/2+(10)/(x^2)

What is the first derivative of f(x)= 3/8 x^4-2-(10)/x ?

The first derivative of f(x)= 3/8 x^4-2-(10)/x is (3x^3)/2+(10)/(x^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

f (x) = \frac{3}{8} x^{4} - 2 - \frac{10}{x}

\frac{3 x ^{3}}{2} + \frac{10}{x ^{2}}

Solution steps

\frac{d}{d x} (\frac{3}{8} x^{4} - 2 - \frac{10}{x})

Simplify

\frac{3}{8} x^{4} - 2 - \frac{10}{x} : \frac{3 x ^{4}}{8} - 2 - \frac{10}{x}

= \frac{d}{d x} (\frac{3 x ^{4}}{8} - 2 - \frac{10}{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{3 x ^{4}}{8}) - \frac{d}{d x} (2) - \frac{d}{d x} (\frac{10}{x})

\frac{d}{d x} (\frac{3 x ^{4}}{8}) = \frac{3 x ^{3}}{2}

\frac{d}{d x} (2) = 0

\frac{d}{d x} (\frac{10}{x}) = - \frac{10}{x ^{2}}

= \frac{3 x ^{3}}{2} - 0 - (- \frac{10}{x ^{2}})

Simplify

= \frac{3 x ^{3}}{2} + \frac{10}{x ^{2}}

f (x) = (3 x^{2} - 1)^{2}

2 x, y = \frac{1}{3} x

\frac{d}{d x} (x^{3} + 3 x^{2} - 9 x + 4)

x \to 2 lim (k x)

\int 9 - y^{2} d y

What is the derivative of f(x)= 3/8 x^4-2-(10)/x ?
The derivative of f(x)= 3/8 x^4-2-(10)/x is (3x^3)/2+(10)/(x^2)
What is the first derivative of f(x)= 3/8 x^4-2-(10)/x ?
The first derivative of f(x)= 3/8 x^4-2-(10)/x is (3x^3)/2+(10)/(x^2)