What is inverse oflaplace 3/(4s) ?

The answer to inverse oflaplace 3/(4s) is 3/4 \H(t)

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inverse oflaplace 3/(4s)

inverse laplace

\frac{3}{4 s}

\frac{3}{4} H (t)

Solution steps

L^{- 1} {\frac{3}{4 s}}

= L^{- 1} {\frac{1}{4} \cdot \frac{3}{s}}

Use the constant multiplication property of Inverse Laplace Transform:

For function

f (t)

and constant

a : L^{- 1} {a \cdot f (t)} = a \cdot L^{- 1} {f (t)}

= \frac{1}{4} L^{- 1} {\frac{3}{s}}

Use Inverse Laplace Transform table:

L^{- 1} {\frac{a}{s}} = a H (t)

Where

H (t)

is Heaviside step function

= \frac{1}{4} \cdot 3 H (t)

= \frac{3}{4} H (t)

\frac{d}{d x} (sec^{2} (x^{3}))

x \to 2 lim (- x + 7)

\int \frac{x ^{3}}{x ^{4} + 6} d x

f (x) = ln (x^{7}), (1, 0)

\frac{d y}{d x} = \frac{2 x + 5 y}{x}

What is inverse oflaplace 3/(4s) ?
The answer to inverse oflaplace 3/(4s) is 3/4 \H(t)