What is the first derivative of 2ax+b ?

The first derivative of 2ax+b is 2a

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of 2ax+b

derivative of

2 a x + b

2 a

Solution steps

\frac{d}{d x} (2 a x + b)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 a x) + \frac{d b}{d x}

\frac{d}{d x} (2 a x) = 2 a

\frac{d b}{d x} = 0

= 2 a + 0

Simplify

= 2 a

\frac{d y}{d x} = \frac{2 x}{y}

\int_{- 8}^{8} x^{\frac{1}{3}} d x

y^{^{''}} - \frac{1}{x} y^{^{'}} = 3 x

\int_{1}^{4} x^{3} d x

\frac{d}{d x} (cos (x + 2))