What is the limit as x approaches 0+of xe^{-2/x} ?

The limit as x approaches 0+of xe^{-2/x} is 0

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limit as x approaches 0+of xe^{-2/x}

x \to 0 + lim (x e^{- \frac{2}{x}})

0

Solution steps

x \to 0 + lim (x e^{- \frac{2}{x}})

x \to a lim [f (x) \cdot g (x)] = x \to a lim f (x) \cdot x \to a lim g (x)

With the exception of indeterminate form

= x \to 0 + lim (x) \cdot x \to 0 + lim (e^{- \frac{2}{x}})

x \to 0 + lim (x) = 0

x \to 0 + lim (e^{- \frac{2}{x}}) = 0

= 0 \cdot 0

Simplify

= 0

y^{^{'}} + 2 t y = e^{- t^{2}}

\int_{0}^{π} 6 cos^{2} (3 x) d x

\int (x^{2} - 4 x + 5)^{2} d x

(x + 2)^{\frac{2}{3}}

y = \frac{( x - 2 )}{( x - 3 )}

What is the limit as x approaches 0+of xe^{-2/x} ?
The limit as x approaches 0+of xe^{-2/x} is 0