What is the derivative of 9e^x(cos(x)-sin(x)) ?

The derivative of 9e^x(cos(x)-sin(x)) is -18e^xsin(x)

What is the first derivative of 9e^x(cos(x)-sin(x)) ?

The first derivative of 9e^x(cos(x)-sin(x)) is -18e^xsin(x)

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derivative of

9 e^{x} (cos (x) - sin (x))

- 18 e^{x} sin (x)

Solution steps

\frac{d}{d x} (9 e^{x} (cos (x) - sin (x)))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 9 \frac{d}{d x} (e^{x} (cos (x) - sin (x)))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = e^{x}, g = cos (x) - sin (x)

= 9 (\frac{d}{d x} (e^{x}) (cos (x) - sin (x)) + \frac{d}{d x} (cos (x) - sin (x)) e^{x})

\frac{d}{d x} (e^{x}) = e^{x}

\frac{d}{d x} (cos (x) - sin (x)) = - sin (x) - cos (x)

= 9 (e^{x} (cos (x) - sin (x)) + (- sin (x) - cos (x)) e^{x})

Simplify

9 (e^{x} (cos (x) - sin (x)) + (- sin (x) - cos (x)) e^{x}) : - 18 e^{x} sin (x)

= - 18 e^{x} sin (x)

n = 0 \sum \infty (- x)^{n}

x \to 0 + lim (\frac{x}{ln ( \frac{1}{x} )})

\frac{\partial}{\partial x} (\frac{y}{2 x})

x \cdot sin (\frac{4}{x})

x^{^{''}} - 8 x^{^{'}} + 16 x = 4 t e^{4 t}

What is the derivative of 9e^x(cos(x)-sin(x)) ?
The derivative of 9e^x(cos(x)-sin(x)) is -18e^xsin(x)
What is the first derivative of 9e^x(cos(x)-sin(x)) ?
The first derivative of 9e^x(cos(x)-sin(x)) is -18e^xsin(x)