What is the derivative of y=cos((pit)/2-pi/3) ?

The derivative of y=cos((pit)/2-pi/3) is -pi/4 sin((pit)/2)+(sqrt(3)pi)/4 cos((pit)/2)

What is the first derivative of y=cos((pit)/2-pi/3) ?

The first derivative of y=cos((pit)/2-pi/3) is -pi/4 sin((pit)/2)+(sqrt(3)pi)/4 cos((pit)/2)

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derivative of

y = cos (\frac{π t}{2} - \frac{π}{3})

- \frac{π}{4} sin (\frac{π t}{2}) + \frac{3 π}{4} cos (\frac{π t}{2})

Solution steps

\frac{d}{d t} (cos (\frac{π t}{2} - \frac{π}{3}))

Simplify

cos (\frac{π t}{2} - \frac{π}{3}) : \frac{1}{2} cos (\frac{π t}{2}) + \frac{3}{2} sin (\frac{π t}{2})

= \frac{d}{d t} (\frac{1}{2} cos (\frac{π t}{2}) + \frac{3}{2} sin (\frac{π t}{2}))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (\frac{1}{2} cos (\frac{π t}{2})) + \frac{d}{d t} (\frac{3}{2} sin (\frac{π t}{2}))

\frac{d}{d t} (\frac{1}{2} cos (\frac{π t}{2})) = - \frac{π}{4} sin (\frac{π t}{2})

\frac{d}{d t} (\frac{3}{2} sin (\frac{π t}{2})) = \frac{3 π}{4} cos (\frac{π t}{2})

= - \frac{π}{4} sin (\frac{π t}{2}) + \frac{3 π}{4} cos (\frac{π t}{2})

h \to 0 lim (\frac{1 - cos ( 7 h )}{h})

- 2 x^{2} + 2 x

x \to 6 lim (21 x + 18)

x \to - \infty lim (- (x))

\int_{y}^{x} cos (e^{t}) d t

What is the derivative of y=cos((pit)/2-pi/3) ?
The derivative of y=cos((pit)/2-pi/3) is -pi/4 sin((pit)/2)+(sqrt(3)pi)/4 cos((pit)/2)
What is the first derivative of y=cos((pit)/2-pi/3) ?
The first derivative of y=cos((pit)/2-pi/3) is -pi/4 sin((pit)/2)+(sqrt(3)pi)/4 cos((pit)/2)