What is the limit as x approaches 9 of ((16+sqrt(x)))/(sqrt(16+x)) ?

The limit as x approaches 9 of ((16+sqrt(x)))/(sqrt(16+x)) is 19/5

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limit as x approaches 9 of ((16+sqrt(x)))/(sqrt(16+x))

x \to 9 lim (\frac{( 16 + x )}{16 + x})

\frac{19}{5}

Solution steps

x \to 9 lim (\frac{16 + x}{16 + x})

Plug in the value

x = 9

= \frac{16 + 9}{16 + 9}

Simplify

\frac{16 + 9}{16 + 9} : \frac{19}{5}

= \frac{19}{5}

f (x) = e^{\frac{x}{2}}

{\frac{( s + 1 ) ^{2}}{s ^{3}}}

y^{^{'}} = \frac{x y ^{3}}{25}

\frac{\partial}{\partial y} (1 - y^{2})

2 sin (x)

What is the limit as x approaches 9 of ((16+sqrt(x)))/(sqrt(16+x)) ?
The limit as x approaches 9 of ((16+sqrt(x)))/(sqrt(16+x)) is 19/5