What is the derivative of f(x)=4x-3 ?

The derivative of f(x)=4x-3 is 4

What is the first derivative of f(x)=4x-3 ?

The first derivative of f(x)=4x-3 is 4

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derivative of

f (x) = 4 x - 3

4

Solution steps

\frac{d}{d x} (4 x - 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x) - \frac{d}{d x} (3)

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (3) = 0

= 4 - 0

Simplify

= 4

y = 4 e^{- x} + e^{3 x}

\frac{d}{d x} (x^{3} - 6 x^{2} + 9 x - 1)

\frac{d}{d x} (\frac{x - y}{x + y})

\int (x^{2} - 3 x + 5) d x

f (x) = x^{2} + x, at x = 1, at x = 3

What is the derivative of f(x)=4x-3 ?
The derivative of f(x)=4x-3 is 4
What is the first derivative of f(x)=4x-3 ?
The first derivative of f(x)=4x-3 is 4