What is the derivative of (2x^2+5x)/x ?

The derivative of (2x^2+5x)/x is 2

What is the first derivative of (2x^2+5x)/x ?

The first derivative of (2x^2+5x)/x is 2

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derivative of

\frac{2 x ^{2} + 5 x}{x}

2

Solution steps

\frac{d}{d x} (\frac{2 x ^{2} + 5 x}{x})

Simplify

\frac{2 x ^{2} + 5 x}{x} : 2 x + 5

= \frac{d}{d x} (2 x + 5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x) + \frac{d}{d x} (5)

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (5) = 0

= 2 + 0

Simplify

= 2

\frac{2}{s + 2}

\int \frac{2 x}{1 - x ^{2}} d x

R (x) = [x^{2} (x^{2} + 6 x)]^{4}

\frac{d}{d x} (tanh (1 + e^{2 x}))

y = \frac{1}{16} (e^{8 x} + e^{- 8 x}), - 4 \leq x \leq 4

What is the derivative of (2x^2+5x)/x ?
The derivative of (2x^2+5x)/x is 2
What is the first derivative of (2x^2+5x)/x ?
The first derivative of (2x^2+5x)/x is 2