What is the d/(dh)(35{f}(h)(3+2h)) ?

The d/(dh)(35{f}(h)(3+2h)) is 35(d/(dh)({f}(h))(3+2h)+2{f}(h))

What is the first d/(dh)(35{f}(h)(3+2h)) ?

The first d/(dh)(35{f}(h)(3+2h)) is 35(d/(dh)({f}(h))(3+2h)+2{f}(h))

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\frac{d}{d h} (35 f (h) (3 + 2 h))

35 (\frac{d}{d h} (f (h)) (3 + 2 h) + 2 f (h))

Solution steps

\frac{d}{d h} (35 f (h) (3 + 2 h))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 35 \frac{d}{d h} (f (h) (3 + 2 h))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = f (h), g = 3 + 2 h

= 35 (\frac{d}{d h} (f (h)) (3 + 2 h) + \frac{d}{d h} (3 + 2 h) f (h))

\frac{d}{d h} (3 + 2 h) = 2

= 35 (\frac{d}{d h} (f (h)) (3 + 2 h) + 2 f (h))

(1 + \frac{x}{2})^{- 4}

\int 16 - x d x

3 x^{2} y^{^{''}} + 7 x y^{^{'}} + y = 24 x + 2

\frac{d}{d x} (3 x^{2} - 4 x y^{4} - y^{3})

x \to 1 lim (ln (0))

What is the d/(dh)(35{f}(h)(3+2h)) ?
The d/(dh)(35{f}(h)(3+2h)) is 35(d/(dh)({f}(h))(3+2h)+2{f}(h))
What is the first d/(dh)(35{f}(h)(3+2h)) ?
The first d/(dh)(35{f}(h)(3+2h)) is 35(d/(dh)({f}(h))(3+2h)+2{f}(h))