What is laplacetransform 13sin(2t) ?

The answer to laplacetransform 13sin(2t) is (26)/(s^2+4)

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laplacetransform 13sin(2t)

laplace transform

13 sin (2 t)

\frac{26}{s ^{2} + 4}

Solution steps

L {13 sin (2 t)}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= 13 L {sin (2 t)}

L {sin (2 t)} : \frac{2}{s ^{2} + 4}

= 13 \cdot \frac{2}{s ^{2} + 4}

Refine

13 \frac{2}{s ^{2} + 4} : \frac{26}{s ^{2} + 4}

= \frac{26}{s ^{2} + 4}

\int (\frac{10}{1 - sin ^{2} ( x )}) d x

n = 1 \sum \infty \frac{( ( - 1 ) ^{(n - 1)} )}{( n ^{3} )}

y^{^{'}} + 2 y = 3

x \to 2 - lim (2 - x)

x \to 2 - lim (\frac{1}{x - 2})

What is laplacetransform 13sin(2t) ?
The answer to laplacetransform 13sin(2t) is (26)/(s^2+4)