What is the derivative of-bsin(x) ?

The derivative of-bsin(x) is -bcos(x)

What is the first derivative of-bsin(x) ?

The first derivative of-bsin(x) is -bcos(x)

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\frac{d}{d x} (- b sin (x))

- b cos (x)

Solution steps

\frac{d}{d x} (- b sin (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - b \frac{d}{d x} (sin (x))

Apply the common derivative:

\frac{d}{d x} (sin (x)) = cos (x)

= - b cos (x)

\frac{d}{d t} (\frac{t}{( t - 1 ) ^{2}})

n = 0 \sum \infty \frac{n}{n ^{3} + 4}

x^{6} + y^{2} = 2, (1, - 1)

\frac{d}{d x} (2 A + B (e^{x} x^{2} + 4 e^{x} x + 2 e^{x}))

x y^{^{'}} + 2 y = 3 cos (x)

What is the derivative of-bsin(x) ?
The derivative of-bsin(x) is -bcos(x)
What is the first derivative of-bsin(x) ?
The first derivative of-bsin(x) is -bcos(x)