What is the derivative of g(x)=sqrt(1+2x) ?

The derivative of g(x)=sqrt(1+2x) is 1/(sqrt(1+2x))

What is the first derivative of g(x)=sqrt(1+2x) ?

The first derivative of g(x)=sqrt(1+2x) is 1/(sqrt(1+2x))

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derivative of

g (x) = 1 + 2 x

\frac{1}{1 + 2 x}

Solution steps

\frac{d}{d x} (1 + 2 x)

Apply the chain rule:

\frac{1}{2 1 + 2 x} \frac{d}{d x} (1 + 2 x)

= \frac{1}{2 1 + 2 x} \frac{d}{d x} (1 + 2 x)

\frac{d}{d x} (1 + 2 x) = 2

= \frac{1}{2 1 + 2 x} \cdot 2

Simplify

\frac{1}{2 1 + 2 x} \cdot 2 : \frac{1}{1 + 2 x}

= \frac{1}{1 + 2 x}

n = 1 \sum \infty (\frac{cos ( π )}{3})^{n}

\int_{0}^{\frac{π}{4}} sin^{3} (x) d x

\frac{\partial}{\partial y} (\frac{2 x}{x ^{2} + y})

16 y^{^{''}} + 8 y^{^{'}} + y = x + 6

\frac{d y}{d x} = (\frac{x y + 3 x - y - 3}{x y - 2 x + 4 y - 8})

What is the derivative of g(x)=sqrt(1+2x) ?
The derivative of g(x)=sqrt(1+2x) is 1/(sqrt(1+2x))
What is the first derivative of g(x)=sqrt(1+2x) ?
The first derivative of g(x)=sqrt(1+2x) is 1/(sqrt(1+2x))