What is the sum from n=1 to infinity of 1/(3^n+5) ?

The sum from n=1 to infinity of 1/(3^n+5) is converges

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sum from n=1 to infinity of 1/(3^n+5)

n = 1 \sum \infty \frac{1}{3 ^{n} + 5}

converges

Solution steps

n = 1 \sum \infty \frac{1}{3 ^{n} + 5}

Apply Series Ratio Test:

converges

= converges

\frac{\partial}{\partial x} (2 x + 4 y)

n = 1 \sum \infty \frac{6}{π \cdot n}

\int x^{- \frac{3}{4}} + 4 e^{x} d x

\frac{d}{d x} (156 - \frac{x ^{2}}{39})

What is the sum from n=1 to infinity of 1/(3^n+5) ?
The sum from n=1 to infinity of 1/(3^n+5) is converges