What is the derivative of sec^2(θ)-3 ?

The derivative of sec^2(θ)-3 is 2sec^2(θ)tan(θ)

What is the first derivative of sec^2(θ)-3 ?

The first derivative of sec^2(θ)-3 is 2sec^2(θ)tan(θ)

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derivative of

sec^{2} (θ) - 3

2 sec^{2} (θ) tan (θ)

Solution steps

\frac{d}{d θ} (sec^{2} (θ) - 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d θ} (sec^{2} (θ)) - \frac{d}{d θ} (3)

\frac{d}{d θ} (sec^{2} (θ)) = 2 sec^{2} (θ) tan (θ)

\frac{d}{d θ} (3) = 0

= 2 sec^{2} (θ) tan (θ) - 0

Simplify

= 2 sec^{2} (θ) tan (θ)

\frac{d}{d x} (\frac{x ^{2} - 4}{x ^{2} + 1})

y = 220 + 65 x

f (x) = \frac{x}{x + 8}

(15 x y^{2} - 4 y) + (15 x^{2} y - 4 x) y^{^{'}} = 0

n = 1 \sum \infty \frac{1}{2 ^{n} - 1}

What is the derivative of sec^2(θ)-3 ?
The derivative of sec^2(θ)-3 is 2sec^2(θ)tan(θ)
What is the first derivative of sec^2(θ)-3 ?
The first derivative of sec^2(θ)-3 is 2sec^2(θ)tan(θ)