What is the solution for x(dy)/(dx)+(2x+1)y=e^{-2x} ?

The solution for x(dy)/(dx)+(2x+1)y=e^{-2x} is y= 1/(e^{2x)}+(c_{1})/(e^{2x)x}

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x(dy)/(dx)+(2x+1)y=e^{-2x}

x \frac{d y}{d x} + (2 x + 1) y = e^{- 2 x}

y = \frac{1}{e ^{2 x}} + \frac{c _{1}}{e ^{2 x} x}

Solution steps

x \frac{d y}{d x} + (2 x + 1) y = e^{- 2 x}

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y = \frac{1}{e ^{2 x}} + \frac{c _{1}}{e ^{2 x} x}

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What is the solution for x(dy)/(dx)+(2x+1)y=e^{-2x} ?
The solution for x(dy)/(dx)+(2x+1)y=e^{-2x} is y= 1/(e^{2x)}+(c_{1})/(e^{2x)x}