What is the d/(dt)(cos(2t)) ?

The d/(dt)(cos(2t)) is -sin(2t)*2

What is the first d/(dt)(cos(2t)) ?

The first d/(dt)(cos(2t)) is -sin(2t)*2

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\frac{d}{d t} (cos (2 t))

- sin (2 t) \cdot 2

Solution steps

\frac{d}{d t} (cos (2 t))

Apply the chain rule:

- sin (2 t) \frac{d}{d t} (2 t)

= - sin (2 t) \frac{d}{d t} (2 t)

\frac{d}{d t} (2 t) = 2

= - sin (2 t) \cdot 2

\frac{d}{d x} ((x + 1) (2 x + 5)^{4})

\int e^{- \frac{x}{2}} d x

\frac{x ^{2} - 6 x}{x + 1}

y = x^{2} - 2 x, y = x + 4

\frac{d}{d x} (x cos (x) - sin (x) ln (cos (x)))