What is the derivative of (x^2-6x)/(x+1) ?

The derivative of (x^2-6x)/(x+1) is (x^2+2x-6)/((x+1)^2)

What is the first derivative of (x^2-6x)/(x+1) ?

The first derivative of (x^2-6x)/(x+1) is (x^2+2x-6)/((x+1)^2)

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derivative of

\frac{x ^{2} - 6 x}{x + 1}

\frac{x ^{2} + 2 x - 6}{( x + 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x ^{2} - 6 x}{x + 1})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ^{2} - 6 x ) ( x + 1 ) - \frac{d}{d x} ( x + 1 ) ( x ^{2} - 6 x )}{( x + 1 ) ^{2}}

\frac{d}{d x} (x^{2} - 6 x) = 2 x - 6

\frac{d}{d x} (x + 1) = 1

= \frac{( 2 x - 6 ) ( x + 1 ) - 1 \cdot ( x ^{2} - 6 x )}{( x + 1 ) ^{2}}

Simplify

\frac{( 2 x - 6 ) ( x + 1 ) - 1 \cdot ( x ^{2} - 6 x )}{( x + 1 ) ^{2}} : \frac{x ^{2} + 2 x - 6}{( x + 1 ) ^{2}}

= \frac{x ^{2} + 2 x - 6}{( x + 1 ) ^{2}}

y = x^{2} - 2 x, y = x + 4

\frac{d}{d x} (x cos (x) - sin (x) ln (cos (x)))

\frac{d}{d x} (c e^{- 3 x})

f (x) = \frac{120 x ^{2}}{x ^{2} + 4}

\frac{d}{d x} (ln ∣ x + 2 ∣)

What is the derivative of (x^2-6x)/(x+1) ?
The derivative of (x^2-6x)/(x+1) is (x^2+2x-6)/((x+1)^2)
What is the first derivative of (x^2-6x)/(x+1) ?
The first derivative of (x^2-6x)/(x+1) is (x^2+2x-6)/((x+1)^2)