What is the limit as x approaches 4/3 of 2x^2-4x+5 ?

The limit as x approaches 4/3 of 2x^2-4x+5 is 29/9

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limit as x approaches 4/3 of 2x^2-4x+5

x \to \frac{4}{3} lim (2 x^{2} - 4 x + 5)

\frac{29}{9}

Decimal

3.22222 \dots

Solution steps

x \to \frac{4}{3} lim (2 x^{2} - 4 x + 5)

Plug in the value

x = \frac{4}{3}

= 2 (\frac{4}{3})^{2} - 4 \cdot \frac{4}{3} + 5

Simplify

2 (\frac{4}{3})^{2} - 4 \cdot \frac{4}{3} + 5 : \frac{29}{9}

= \frac{29}{9}

\int x (3^{- x^{2}}) d x

x \to 1 lim (1.7496)

f (x) = 12 x

h \to 0 lim (4 - h)

y = sin (x) tan (x)

What is the limit as x approaches 4/3 of 2x^2-4x+5 ?
The limit as x approaches 4/3 of 2x^2-4x+5 is 29/9