What is the derivative of y=sin(x)tan(x) ?

The derivative of y=sin(x)tan(x) is sin(x)(1+sec^2(x))

What is the first derivative of y=sin(x)tan(x) ?

The first derivative of y=sin(x)tan(x) is sin(x)(1+sec^2(x))

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derivative of

y = sin (x) tan (x)

sin (x) (1 + sec^{2} (x))

Solution steps

\frac{d}{d x} (sin (x) tan (x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = sin (x), g = tan (x)

= \frac{d}{d x} (sin (x)) tan (x) + \frac{d}{d x} (tan (x)) sin (x)

\frac{d}{d x} (sin (x)) = cos (x)

\frac{d}{d x} (tan (x)) = sec^{2} (x)

= cos (x) tan (x) + sec^{2} (x) sin (x)

Simplify

cos (x) tan (x) + sec^{2} (x) sin (x) : sin (x) (1 + sec^{2} (x))

= sin (x) (1 + sec^{2} (x))

\frac{d}{d x} (3 cos^{4} (x))

(2, 8), y = 2 x^{2}

\frac{d}{d x} (r (t, x) cos (t))

x \to 0 lim (\frac{1 - cos ( 4 x )}{x tan ( 3 x )})

\frac{\partial}{\partial x} (- 2 e^{- 7 x y})

What is the derivative of y=sin(x)tan(x) ?
The derivative of y=sin(x)tan(x) is sin(x)(1+sec^2(x))
What is the first derivative of y=sin(x)tan(x) ?
The first derivative of y=sin(x)tan(x) is sin(x)(1+sec^2(x))