What is (\partial)/(\partial x)(-2e^{-7xy}) ?

The answer to (\partial)/(\partial x)(-2e^{-7xy}) is 14e^{-7xy}y

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(\partial)/(\partial x)(-2e^{-7xy})

\frac{\partial}{\partial x} (- 2 e^{- 7 x y})

14 e^{- 7 x y} y

Solution steps

\frac{\partial}{\partial x} (- 2 e^{- 7 x y})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 2 \frac{\partial}{\partial x} (e^{- 7 x y})

Apply the chain rule:

e^{- 7 x y} \frac{\partial}{\partial x} (- 7 x y)

= e^{- 7 x y} \frac{\partial}{\partial x} (- 7 x y)

\frac{\partial}{\partial x} (- 7 x y) = - 7 y

= - 2 e^{- 7 x y} (- 7 y)

Simplify

= 14 e^{- 7 x y} y

\int - \frac{1}{cos ( x )} d x

\frac{d}{d x} (\frac{3}{6 - x})

\frac{d}{d x} (3 x^{4} + 15)

e^{6 x} cos (9 x)

y = \frac{4}{x}, (- 4, - 1)

What is (\partial)/(\partial x)(-2e^{-7xy}) ?
The answer to (\partial)/(\partial x)(-2e^{-7xy}) is 14e^{-7xy}y