What is the derivative of 7/10 x^2+4^3 ?

The derivative of 7/10 x^2+4^3 is (7x)/5

What is the first derivative of 7/10 x^2+4^3 ?

The first derivative of 7/10 x^2+4^3 is (7x)/5

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\frac{d}{d x} (\frac{7}{10} x^{2} + 4^{3})

\frac{7 x}{5}

Solution steps

\frac{d}{d x} (\frac{7}{10} x^{2} + 4^{3})

Simplify

\frac{7}{10} x^{2} + 4^{3} : \frac{7 x ^{2}}{10} + 64

= \frac{d}{d x} (\frac{7 x ^{2}}{10} + 64)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{7 x ^{2}}{10}) + \frac{d}{d x} (64)

\frac{d}{d x} (\frac{7 x ^{2}}{10}) = \frac{7 x}{5}

\frac{d}{d x} (64) = 0

= \frac{7 x}{5} + 0

Simplify

= \frac{7 x}{5}

\frac{d y}{d x} = \frac{18 ( 2 + y ) ^{2}}{( 1 - 3 x ) ^{2}}

\int (x^{2} - 2 x + 3) ln (x) d x

x \to 0 lim (3 (x^{\frac{x}{2}}))

f (x) = \frac{6}{5 x + 3}, at x = - 1

x^{^{'}} = x + 1

What is the derivative of 7/10 x^2+4^3 ?
The derivative of 7/10 x^2+4^3 is (7x)/5
What is the first derivative of 7/10 x^2+4^3 ?
The first derivative of 7/10 x^2+4^3 is (7x)/5