What is the tangent of f(x)= 6/(5x+3),\at x=-1 ?

The tangent of f(x)= 6/(5x+3),\at x=-1 is y=-15/2 x-21/2

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tangent of f(x)= 6/(5x+3),\at x=-1

tangent of

f (x) = \frac{6}{5 x + 3}, at x = - 1

y = - \frac{15}{2} x - \frac{21}{2}

Solution steps

Find the tangent point:

(- 1, - 3)

Find the slope of

f (x) = \frac{6}{5 x + 3} : \frac{df ( x )}{d x} = - \frac{30}{( 5 x + 3 ) ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{15}{2}

Find the line with slope m=

- \frac{15}{2}

and passing through

(- 1, - 3) : y = - \frac{15}{2} x - \frac{21}{2}

y = - \frac{15}{2} x - \frac{21}{2}

x^{^{'}} = x + 1

f (x) = 9 x e^{- k x}

- x^{- 3}

\frac{\partial}{\partial z} (y - x - z)

\frac{d}{d x} (- 3 x^{\frac{1}{2}})

What is the tangent of f(x)= 6/(5x+3),\at x=-1 ?
The tangent of f(x)= 6/(5x+3),\at x=-1 is y=-15/2 x-21/2