What is the derivative of-8e^{-2x} ?

The derivative of-8e^{-2x} is 16e^{-2x}

What is the first derivative of-8e^{-2x} ?

The first derivative of-8e^{-2x} is 16e^{-2x}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (- 8 e^{- 2 x})

16 e^{- 2 x}

Solution steps

\frac{d}{d x} (- 8 e^{- 2 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 8 \frac{d}{d x} (e^{- 2 x})

Apply the chain rule:

e^{- 2 x} \frac{d}{d x} (- 2 x)

= e^{- 2 x} \frac{d}{d x} (- 2 x)

\frac{d}{d x} (- 2 x) = - 2

= - 8 e^{- 2 x} (- 2)

Simplify

= 16 e^{- 2 x}

x \to 4 lim (2 \cdot e^{\frac{2}{x - 4}})

x \to 0 lim ((- 3) sin (7 x))

y^{^{''}} - 1 = 0

\int ln ∣ x ∣ \cdot 1 d x

\int sin (10 x) sin (15 x) d x

What is the derivative of-8e^{-2x} ?
The derivative of-8e^{-2x} is 16e^{-2x}
What is the first derivative of-8e^{-2x} ?
The first derivative of-8e^{-2x} is 16e^{-2x}