What is the derivative of 6cos(θ)+3sin^2(θ) ?

The derivative of 6cos(θ)+3sin^2(θ) is -6sin(θ)+3sin(2θ)

What is the first derivative of 6cos(θ)+3sin^2(θ) ?

The first derivative of 6cos(θ)+3sin^2(θ) is -6sin(θ)+3sin(2θ)

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derivative of

6 cos (θ) + 3 sin^{2} (θ)

- 6 sin (θ) + 3 sin (2 θ)

Solution steps

\frac{d}{d θ} (6 cos (θ) + 3 sin^{2} (θ))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d θ} (6 cos (θ)) + \frac{d}{d θ} (3 sin^{2} (θ))

\frac{d}{d θ} (6 cos (θ)) = - 6 sin (θ)

\frac{d}{d θ} (3 sin^{2} (θ)) = 3 sin (2 θ)

= - 6 sin (θ) + 3 sin (2 θ)

- 2 x (x^{2} + 1)^{- 2}

x - 2^{- x}

\frac{u}{u + \frac{c}{u}}

\int (sin (x + y)) d x

(2 x^{4} - 1) (5 x^{3} + 6 x)

What is the derivative of 6cos(θ)+3sin^2(θ) ?
The derivative of 6cos(θ)+3sin^2(θ) is -6sin(θ)+3sin(2θ)
What is the first derivative of 6cos(θ)+3sin^2(θ) ?
The first derivative of 6cos(θ)+3sin^2(θ) is -6sin(θ)+3sin(2θ)