What is the derivative of f(x)=x^3+x-3 ?

The derivative of f(x)=x^3+x-3 is 3x^2+1

What is the first derivative of f(x)=x^3+x-3 ?

The first derivative of f(x)=x^3+x-3 is 3x^2+1

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derivative of

f (x) = x^{3} + x - 3

3 x^{2} + 1

Solution steps

\frac{d}{d x} (x^{3} + x - 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) + \frac{d x}{d x} - \frac{d}{d x} (3)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d x}{d x} = 1

\frac{d}{d x} (3) = 0

= 3 x^{2} + 1 - 0

Simplify

= 3 x^{2} + 1

y = 2 sin (3 x)

x \to 0 lim (x cos (\frac{6}{x}))

x \to - 3 + lim (\frac{- 7 x}{x + 3})

\int \frac{x}{4 - 3 x ^{2}} d x

x \to 0 lim (\frac{x + 97}{x})

What is the derivative of f(x)=x^3+x-3 ?
The derivative of f(x)=x^3+x-3 is 3x^2+1
What is the first derivative of f(x)=x^3+x-3 ?
The first derivative of f(x)=x^3+x-3 is 3x^2+1