What is the derivative of y=2sin(3x) ?

The derivative of y=2sin(3x) is 6cos(3x)

What is the first derivative of y=2sin(3x) ?

The first derivative of y=2sin(3x) is 6cos(3x)

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derivative of

y = 2 sin (3 x)

6 cos (3 x)

Solution steps

\frac{d}{d x} (2 sin (3 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (sin (3 x))

Apply the chain rule:

cos (3 x) \frac{d}{d x} (3 x)

= cos (3 x) \frac{d}{d x} (3 x)

\frac{d}{d x} (3 x) = 3

= 2 cos (3 x) \cdot 3

Simplify

= 6 cos (3 x)

x \to 0 lim (x cos (\frac{6}{x}))

x \to - 3 + lim (\frac{- 7 x}{x + 3})

\int \frac{x}{4 - 3 x ^{2}} d x

x \to 0 lim (\frac{x + 97}{x})

x y^{^{'}} - 2 y = 2 x^{2} + 2 x + 2

What is the derivative of y=2sin(3x) ?
The derivative of y=2sin(3x) is 6cos(3x)
What is the first derivative of y=2sin(3x) ?
The first derivative of y=2sin(3x) is 6cos(3x)