What is the limit as x approaches 1+of 8/(x^3-1) ?

The limit as x approaches 1+of 8/(x^3-1) is infinity

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limit as x approaches 1+of 8/(x^3-1)

x \to 1 + lim (\frac{8}{x ^{3} - 1})

\infty

Solution steps

x \to 1 + lim (\frac{8}{x ^{3} - 1})

For

x

approaching

1

from the right

, x > 1 \Rightarrow x^{3} - 1 > 0

The denominator is a positive quantity approaching 0 from the right

= \infty

f (x) = (x^{3} - 9 x)^{10}, (- 3, 0)

\frac{d}{d x} (x^{y z})

2 cos^{2} (y) d x + tan (y) d y = 0

\frac{d}{d x} (\frac{3}{2 x})

\frac{\partial}{\partial y} (3 + x ln (x y - 7))

What is the limit as x approaches 1+of 8/(x^3-1) ?
The limit as x approaches 1+of 8/(x^3-1) is infinity