What is the tangent of f(x)=(x^3-9x)^{10},(-3,0) ?

The tangent of f(x)=(x^3-9x)^{10},(-3,0) is y=0

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tangent of f(x)=(x^3-9x)^{10},(-3,0)

tangent of

f (x) = (x^{3} - 9 x)^{10}, (- 3, 0)

y = 0

Solution steps

Find the slope of

f (x) = (x^{3} - 9 x)^{10} : \frac{df ( x )}{d x} = 10 (x^{3} - 9 x)^{9} (3 x^{2} - 9)

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 0

Find the line with slope m=

0

and passing through

(- 3, 0) : y = 0

y = 0

\frac{d}{d x} (x^{y z})

2 cos^{2} (y) d x + tan (y) d y = 0

\frac{d}{d x} (\frac{3}{2 x})

\frac{\partial}{\partial y} (3 + x ln (x y - 7))

f (x) = 1 + x^{2}

What is the tangent of f(x)=(x^3-9x)^{10},(-3,0) ?
The tangent of f(x)=(x^3-9x)^{10},(-3,0) is y=0