What is the integral from-1 to 1 of ((1)-(x^2)) ?

The integral from-1 to 1 of ((1)-(x^2)) is 4/3

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integral from-1 to 1 of ((1)-(x^2))

\int_{- 1}^{1} ((1) - (x^{2})) d x

\frac{4}{3}

Decimal

1.33333 \dots

Solution steps

\int_{- 1}^{1} 1 - x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{1} 1 d x - \int_{- 1}^{1} x^{2} d x

\int_{- 1}^{1} 1 d x = 2

\int_{- 1}^{1} x^{2} d x = \frac{2}{3}

= 2 - \frac{2}{3}

Simplify

2 - \frac{2}{3} : \frac{4}{3}

= \frac{4}{3}

\frac{\partial}{\partial y} ((x + y)^{2} + (x + 1)^{2})

n = 2 \sum \infty \frac{1}{n 4 ^{n}}

6 e^{x} cos (x)

f (x) = - \frac{1}{( 5 x + 1 ) ^{2}}

4 y^{^{''}} + y^{^{'}} = 0

What is the integral from-1 to 1 of ((1)-(x^2)) ?
The integral from-1 to 1 of ((1)-(x^2)) is 4/3