What is the solution for x^2dy=(x^2+xy+y^2)dx ?

The solution for x^2dy=(x^2+xy+y^2)dx is y=tan(ln(x)+c_{1})x

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x^2dy=(x^2+xy+y^2)dx

x^{2} d y = (x^{2} + x y + y^{2}) d x

y = tan (ln (x) + c_{1}) x

Solution steps

x^{2} d y = (x^{2} + x y + y^{2}) d x

Solve using substitution:

y = tan (ln (x) + c_{1}) x

y = tan (ln (x) + c_{1}) x

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What is the solution for x^2dy=(x^2+xy+y^2)dx ?
The solution for x^2dy=(x^2+xy+y^2)dx is y=tan(ln(x)+c_{1})x