What is the limit as x approaches 0 of 2^{-1/x} ?

The limit as x approaches 0 of 2^{-1/x} is diverges

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limit as x approaches 0 of 2^{-1/x}

x \to 0 lim (2^{- \frac{1}{x}})

diverges

Solution steps

x \to 0 lim (2^{- \frac{1}{x}})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (2^{- \frac{1}{x}}) = 0

x \to 0 - lim (2^{- \frac{1}{x}}) = \infty

= diverges

\frac{\partial}{\partial y} (y + x cos (t))

\frac{d}{d x} (\frac{1}{x ^{2} + y ^{2}} + x e^{- y})

5 x^{3} - 4 x^{2} - 11

x \to - 3 - lim (\frac{1}{x + 3})

\frac{d}{d x} (sin (x^{3}) cos^{3} (x))

What is the limit as x approaches 0 of 2^{-1/x} ?
The limit as x approaches 0 of 2^{-1/x} is diverges