What is implicit (dy)/(dx),y=x^{3x} ?

The answer to implicit (dy)/(dx),y=x^{3x} is (dy)/(dx)=3x^{3x}(ln(x)+1)

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implicit (dy)/(dx),y=x^{3x}

implicit derivative

\frac{d y}{d x}, y = x^{3 x}

\frac{d y}{d x} = 3 x^{3 x} (ln (x) + 1)

Solution steps

y = x^{3 x}

Treat

y

y (x)

Differentiate both sides:

\frac{d y}{d x} = 3 x^{3 x} (ln (x) + 1)

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = 3 x^{3 x} (ln (x) + 1)

\frac{d y}{d x} = 3 x^{3 x} (ln (x) + 1)

f (x) = t

\frac{d}{d x} (\frac{1}{x ^{2}} + \frac{1}{x ^{6}})

\frac{d}{d x} (\frac{3 x ^{4}}{5})

\frac{s}{s ^{2} + 6 s + 10}

y^{^{''}} + 7 y^{^{'}} = 0, y (0) = - 5, y^{^{'}} (0) = - 21

What is implicit (dy)/(dx),y=x^{3x} ?
The answer to implicit (dy)/(dx),y=x^{3x} is (dy)/(dx)=3x^{3x}(ln(x)+1)