What is the derivative of (x^2+4x+6^5) ?

The derivative of (x^2+4x+6^5) is 5(x^2+4x+6)^4(2x+4)

What is the first derivative of (x^2+4x+6^5) ?

The first derivative of (x^2+4x+6^5) is 5(x^2+4x+6)^4(2x+4)

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\frac{d}{d x} ((x^{2} + 4 x + 6)^{5})

5 (x^{2} + 4 x + 6)^{4} (2 x + 4)

Solution steps

\frac{d}{d x} ((x^{2} + 4 x + 6)^{5})

Apply the chain rule:

5 (x^{2} + 4 x + 6)^{4} \frac{d}{d x} (x^{2} + 4 x + 6)

= 5 (x^{2} + 4 x + 6)^{4} \frac{d}{d x} (x^{2} + 4 x + 6)

\frac{d}{d x} (x^{2} + 4 x + 6) = 2 x + 4

= 5 (x^{2} + 4 x + 6)^{4} (2 x + 4)

\int 24

y = \frac{1}{4} (6 t^{2} + 8)

\int \frac{1}{6} (e^{6 x}) d x

y = cos (e^{x})

n = 0 \sum \infty \frac{n ^{5}}{2 ^{n}}

What is the derivative of (x^2+4x+6^5) ?
The derivative of (x^2+4x+6^5) is 5(x^2+4x+6)^4(2x+4)
What is the first derivative of (x^2+4x+6^5) ?
The first derivative of (x^2+4x+6^5) is 5(x^2+4x+6)^4(2x+4)