What is the sum from n=0 to infinity of (n^5)/(2^n) ?

The sum from n=0 to infinity of (n^5)/(2^n) is converges

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sum from n=0 to infinity of (n^5)/(2^n)

n = 0 \sum \infty \frac{n ^{5}}{2 ^{n}}

converges

Solution steps

n = 0 \sum \infty \frac{n ^{5}}{2 ^{n}}

Apply Series Ratio Test:

converges

= converges

f (x) = \frac{8}{x ^{2} + 4}, (2, 1)

x \to \infty lim (2)

\int_{0}^{\infty} 8 x e^{2 x} d x

\frac{\partial}{\partial x} (7 x^{8} y^{4} + 9 x^{7} y^{6})

\int 2 e^{3 y} d y

What is the sum from n=0 to infinity of (n^5)/(2^n) ?
The sum from n=0 to infinity of (n^5)/(2^n) is converges