What is the tangent of f(x)= 8/(x^2+4),(2,1) ?

The tangent of f(x)= 8/(x^2+4),(2,1) is y=-1/2 x+2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)= 8/(x^2+4),(2,1)

tangent of

f (x) = \frac{8}{x ^{2} + 4}, (2, 1)

y = - \frac{1}{2} x + 2

Solution steps

Find the slope of

f (x) = \frac{8}{x ^{2} + 4} : \frac{df ( x )}{d x} = - \frac{16 x}{( x ^{2} + 4 ) ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{1}{2}

Find the line with slope m=

- \frac{1}{2}

and passing through

(2, 1) : y = - \frac{1}{2} x + 2

y = - \frac{1}{2} x + 2

x \to \infty lim (2)

\int_{0}^{\infty} 8 x e^{2 x} d x

\frac{\partial}{\partial x} (7 x^{8} y^{4} + 9 x^{7} y^{6})

\int 2 e^{3 y} d y

\frac{\partial}{\partial z} (x^{2} + 8 z)

What is the tangent of f(x)= 8/(x^2+4),(2,1) ?
The tangent of f(x)= 8/(x^2+4),(2,1) is y=-1/2 x+2