What is the tangent of f(x)=3x^2-x+7,\at x=2 ?

The tangent of f(x)=3x^2-x+7,\at x=2 is y=11x-5

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tangent of f(x)=3x^2-x+7,\at x=2

tangent of

f (x) = 3 x^{2} - x + 7, at x = 2

y = 11 x - 5

Solution steps

Find the tangent point:

(2, 17)

Find the slope of

f (x) = 3 x^{2} - x + 7 : \frac{df ( x )}{d x} = 6 x - 1

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 11

Find the line with slope m=

11

and passing through

(2, 17) : y = 11 x - 5

y = 11 x - 5

\frac{d}{d x} (tan (5 x^{4}))

\int \frac{sin ( θ )}{cos ^{3} ( θ )} d θ

\frac{d}{d x} ((3 x^{2} - 2)^{3})

\frac{d y}{d x} = 6 x (x - 3)

\int \frac{x + 2}{( x ^{2} + 4 x ) ^{2}} d x

What is the tangent of f(x)=3x^2-x+7,\at x=2 ?
The tangent of f(x)=3x^2-x+7,\at x=2 is y=11x-5