What is the limit as x approaches 0 of 8x+4h-3 ?

The limit as x approaches 0 of 8x+4h-3 is 4h-3

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limit as x approaches 0 of 8x+4h-3

x \to 0 lim (8 x + 4 h - 3)

4 h - 3

Solution steps

x \to 0 lim (8 x + 4 h - 3)

Plug in the value

x = 0

= 8 \cdot 0 + 4 h - 3

Simplify

= 4 h - 3

\frac{d}{d x} (1 - \frac{x ^{2}}{4})

\frac{\partial}{\partial v} (v sin (u))

\int_{0}^{1} \frac{6}{x ( x + 1 )} d x

\int 4 x^{5} d x

- \frac{3}{( x - 3 ) ^{2}}

What is the limit as x approaches 0 of 8x+4h-3 ?
The limit as x approaches 0 of 8x+4h-3 is 4h-3