What is the derivative of-3/((x-3)^2) ?

The derivative of-3/((x-3)^2) is 6/((x-3)^3)

What is the first derivative of-3/((x-3)^2) ?

The first derivative of-3/((x-3)^2) is 6/((x-3)^3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

- \frac{3}{( x - 3 ) ^{2}}

\frac{6}{( x - 3 ) ^{3}}

Solution steps

\frac{d}{d x} (- \frac{3}{( x - 3 ) ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 3 \frac{d}{d x} (\frac{1}{( x - 3 ) ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= - 3 \frac{d}{d x} ((x - 3)^{- 2})

Apply the chain rule:

- \frac{2}{( x - 3 ) ^{3}} \frac{d}{d x} (x - 3)

= - \frac{2}{( x - 3 ) ^{3}} \frac{d}{d x} (x - 3)

\frac{d}{d x} (x - 3) = 1

= - 3 (- \frac{2}{( x - 3 ) ^{3}} \cdot 1)

Simplify

- 3 (- \frac{2}{( x - 3 ) ^{3}} \cdot 1) : \frac{6}{( x - 3 ) ^{3}}

= \frac{6}{( x - 3 ) ^{3}}

\int (7 sec (x) tan (x) + 5 sec^{2} (x)) d x

\int x^{2} x^{3} + 10 d x

\frac{\partial}{\partial x} (3 y e^{8 x})

\frac{\partial}{\partial x} (2 x - 8 y + 8 x y)

x^{4} + 5 y^{4} \frac{x ^{5} + 4 d y}{d x} = 0

What is the derivative of-3/((x-3)^2) ?
The derivative of-3/((x-3)^2) is 6/((x-3)^3)
What is the first derivative of-3/((x-3)^2) ?
The first derivative of-3/((x-3)^2) is 6/((x-3)^3)