What is (\partial)/(\partial x)(3xln(4y+1)) ?

The answer to (\partial)/(\partial x)(3xln(4y+1)) is 3ln(4y+1)

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(\partial)/(\partial x)(3xln(4y+1))

\frac{\partial}{\partial x} (3 x ln (4 y + 1))

3 ln (4 y + 1)

Solution steps

\frac{\partial}{\partial x} (3 x ln (4 y + 1))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 ln (4 y + 1) \frac{\partial}{\partial x} (x)

Apply the common derivative:

\frac{\partial}{\partial x} (x) = 1

= 3 ln (4 y + 1) \cdot 1

Simplify

= 3 ln (4 y + 1)

\frac{\partial}{\partial y} (cos (8 x) sin (4 y))

e^{- 12 t} f + 12 e^{- 12 t} f^{^{'}} = - 4 e^{- 14 t}

6 y^{^{''}} + 18 y^{^{'}} - 24 y = 0

y = \frac{1}{4 x ^{2}}, y = x, y = \frac{x}{16}

\int (12 x + 14) (3 x^{2} + 7 x - 1)^{5} d x

What is (\partial)/(\partial x)(3xln(4y+1)) ?
The answer to (\partial)/(\partial x)(3xln(4y+1)) is 3ln(4y+1)