What is the derivative of (3x^2-x+5(x^2+3x-9)) ?

The derivative of (3x^2-x+5(x^2+3x-9)) is 12x^3+24x^2-50x+24

What is the first derivative of (3x^2-x+5(x^2+3x-9)) ?

The first derivative of (3x^2-x+5(x^2+3x-9)) is 12x^3+24x^2-50x+24

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\frac{d}{d x} ((3 x^{2} - x + 5) (x^{2} + 3 x - 9))

12 x^{3} + 24 x^{2} - 50 x + 24

Solution steps

\frac{d}{d x} ((3 x^{2} - x + 5) (x^{2} + 3 x - 9))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = 3 x^{2} - x + 5, g = x^{2} + 3 x - 9

= \frac{d}{d x} (3 x^{2} - x + 5) (x^{2} + 3 x - 9) + \frac{d}{d x} (x^{2} + 3 x - 9) (3 x^{2} - x + 5)

\frac{d}{d x} (3 x^{2} - x + 5) = 6 x - 1

\frac{d}{d x} (x^{2} + 3 x - 9) = 2 x + 3

= (6 x - 1) (x^{2} + 3 x - 9) + (2 x + 3) (3 x^{2} - x + 5)

Simplify

(6 x - 1) (x^{2} + 3 x - 9) + (2 x + 3) (3 x^{2} - x + 5) : 12 x^{3} + 24 x^{2} - 50 x + 24

= 12 x^{3} + 24 x^{2} - 50 x + 24

\frac{\partial}{\partial y} (2 x^{4} y - 4)

\int sec (17 w) tan (17 w) d w

\frac{d}{d x} (ln (2 x - 1) + 2)

\frac{sin ( q ) + cos ( q )}{cos ( q )}

y^{^{''}} - 10 y^{^{'}} + 21 y = 0

What is the derivative of (3x^2-x+5(x^2+3x-9)) ?
The derivative of (3x^2-x+5(x^2+3x-9)) is 12x^3+24x^2-50x+24
What is the first derivative of (3x^2-x+5(x^2+3x-9)) ?
The first derivative of (3x^2-x+5(x^2+3x-9)) is 12x^3+24x^2-50x+24