What is the derivative of (x+1/4) ?

The derivative of (x+1/4) is 1/4

What is the first derivative of (x+1/4) ?

The first derivative of (x+1/4) is 1/4

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\frac{d}{d x} (\frac{x + 1}{4})

\frac{1}{4}

Solution steps

\frac{d}{d x} (\frac{x + 1}{4})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{4} \frac{d}{d x} (x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{4} (\frac{d x}{d x} + \frac{d}{d x} (1))

\frac{d x}{d x} = 1

\frac{d}{d x} (1) = 0

= \frac{1}{4} (1 + 0)

Simplify

= \frac{1}{4}

x \to 0 lim (\frac{sin ( 4 x )}{x} + 2)

\frac{\partial}{\partial x} (x^{3} + y^{2} - 5 x y)

4 y^{^{''}} - y^{^{'}} = 0

y^{^{'''}} + y^{^{''}} + y^{^{'}} + y = 0

\int_{0}^{7} (50 x + 20) d x

What is the derivative of (x+1/4) ?
The derivative of (x+1/4) is 1/4
What is the first derivative of (x+1/4) ?
The first derivative of (x+1/4) is 1/4